Case 1)

my $VAR = 'ABC@VERSION@DEF' ;

$VAR =~ s/\@VERSION\@/1.2.3.4/g ;

print "<$VAR>\n" ;

Prints <ABC1.2.3.4DEF> as expected.

=========================

Case 2)

Lets say $input_file has a line containing ABC@VERSION@DEF

And I want to replace @VERSION@ by 1.2.3.4 So I do:

`perl -pe 's/\@VERSION\@/1.2.3.4/g' -i $input_file` ;

Which chnages the content in $input_file to

ABC1.2.3.4VERSION1.2.3.4DEF

Why the difference in the two cases ?

What do I need to do to get bahavior like Case 1 in Case 2 ?

I'd suspect some special interpretation of @ at play but it's escaped - but
not sure any ideas ?

--
Affijn, Ruud

@VERSION = qw(aaa bbb);
$_ = `echo perl -pe 's/\@VERSION\@/1.2.3.4/g' -i $input_file`;
$_ = `echo perl -pe 's/\\@VERSION\\@/1.2.3.4/g' -i $input_file`;
$_ = `echo perl -pe 's/\\\@VERSION\\\@/1.2.3.4/g' -i $input_file`;
system  qq{perl -pe 's/\\\@VERSION\\\@/1.2.3.4/g' -i $input_file};

Take a look at 'perldoc backticks'.  In particular, the sections for
   What's wrong with using backticks in a void context?
   How can I call backticks without shell processing?